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A 6 letter password was hashed.
All its consecutive fragments of length 3 were preserved, out of order:
$$ \texttt{ABA},\ \texttt{BAC},\ \texttt{ACB},\ \texttt{CBA}. $$
Reconstruct the original password.
Didactic closure of the level
If you can justify why recurrence is correct and not just use it, you are already at a solid level.
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Answer:
$$ \texttt{ABACBA}. $$
Reconstruction by 2-letter overlaps:
ABA ends in BA $\Rightarrow$ fits with BAC,BAC ends in AC $\Rightarrow$ fits with ACB,ACB ends in CB $\Rightarrow$ fits with CBA.Resulting string:
$$ \texttt{ABACBA}. $$
Verification of consecutive fragments of length 3:
$$ \texttt{ABA},\ \texttt{BAC},\ \texttt{ACB},\ \texttt{CBA}. $$
They match the dice exactly.
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