Answer: No there is no selection of boxes that add up to exactly 100 kg or 150 kg. Explanation: Call the weights of the five boxes $a,b,c,d,e$. The sum of all the pairs is
$$
110+112+113+114+115+116+117+118+120+121=1156.
$$ But each box appears in exactly 4 of those pairs, so
$$
4(a+b+c+d+e)=1156,
$$
and therefore
$$
a+b+c+d+e=289.
$$ Now order the pairs. The difference between consecutive sums allows the individual weights to be reconstructed, except in order. The set turns out to be
$$
54,\ 56,\ 57,\ 58,\ 64.
$$ With those five weights you can verify that:
- no box weighs 100 or 150;
- no couple adds 100 or 150;
- no shortlist adds up to 100 or 150;
- and, since the total is 289, neither do the quaternas nor the five together. Then the forklift cannot be activated with any selection.
$$